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Posted by: tudsy Oct 5 2024, 11:38 PM

Hi

I am having a little problem. The problem is I am getting an undefined array key Age warning in the code below.

I tried to use an earlier version of php (8.2 available) but I still get this warning.

Any help will be appreciated.

Thanks.



$age = " ";





if (!empty($age) ){

$age = $_GET["Age"];

}

Posted by: CharlesEF Oct 6 2024, 03:44 AM

Since you say it's an array error then I have to ask: Are you sure you have a URL query string parameter named 'Age'?

Posted by: tudsy Oct 6 2024, 04:13 AM

QUOTE(CharlesEF @ Oct 6 2024, 06:14 PM)

Posted by: tudsy Oct 6 2024, 07:26 AM

QUOTE(tudsy @ Oct 6 2024, 06:43 PM)

QUOTE(CharlesEF @ Oct 6 2024, 06:14 PM)

Since you say it's an array error then I have to ask: Are you sure you have a URL query string parameter named 'Age'?

Yes.

Posted by: CharlesEF Oct 6 2024, 05:59 PM

Your form has 'method="POST"'. Try the POST array instead of the GET array.

Posted by: abuislam Feb 26 2025, 01:13 AM

Hi @tudsy,

The issue you're facing is due to PHP 8.0+ throwing a warning when accessing an undefined array key. You can fix it by checking if the key exists before using it:

php
Copy
Edit
$age = $_GET["Age"] ?? "";
or

php
Copy
Edit
$age = isset($_GET["Age"]) ? $_GET["Age"] : "";
This way, if Age isn’t set, $age remains an empty string instead of causing a warning.

I recently worked on a project where I had to handle similar PHP warnings while building a website about Surah Yaseen (https://suraheyaseen.com/). Ensuring clean, error-free PHP code was crucial for smooth performance, especially when handling user input dynamically. If you're working on a PHP-based site, making these checks early helps avoid such issues.

Hope this helps! Let me know if you need further clarification.